Question

The area of triangle formed by the tangent, normal drawn at $(1,\sqrt{3})$ to the circle $x^2+y^2=4$ and positive x-axis, is

• A. $2\sqrt{3}$
• B. $\sqrt{3}$
• C. $4\sqrt{3}$
• D. None of these

Answer 1

The correct option is A $2\sqrt{3}$

$T\equiv x+\sqrt{3}y-4=0$

Hence the required area =$\frac{1}{2}\times 4\times \sqrt{3}=2\sqrt{3}.$