Question

The area of triangle whose sides are 4cm, 13 cm and 15 cm is

• A. ${576cm}^2$
• B. ${30cm}^2$
• C. ${26cm}^2$
• D. ${24cm}^2$

Answer 1

The correct option is D ${24cm}^2$

$\frac{s}{2}=\frac{4+13+15}{2}=16cmArea=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{16(16-4)(16-13)(16-15)}=\sqrt{16\times 12\times 3\times 1}={24cm}^2$'