The area of triangle with base $12 c m$ and Height $5 c m$ is

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Solution

The height of triangle is $5 c m$

The base of triangle is $12 c m$

The area of triangle is $\frac{1}{2} \times b \times h$
$= \frac{1}{2} \times 12 \times 5$
$= 30 c m^{2}$

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A circum-circle is drawn around a right triangle PQR. The height and the base of the triangle are 5 cm and 12 cm, respectively. What would be the area of the shaded region?

Q. The Height of triangle when its base is

12 c m

and area is

72 c m^{2}

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The area of triangle with base 12cm and Height 5cm is

The height of triangle is 5cmThe base of triangle is 12cmThe area of triangle is 12×b×h=12×12×5=30cm2

The area of triangle with base $12 c m$ and Height $5 c m$ is

The height of triangle is $5 c m$

The base of triangle is $12 c m$

The area of triangle is $\frac{1}{2} \times b \times h$
$= \frac{1}{2} \times 12 \times 5$
$= 30 c m^{2}$