The area of triangle with base $4 c m$ and height is $3 c m$

6 c m^{2}

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12 c m^{2}

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24 c m^{2}

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3 c m^{2}

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Solution

The correct option is A $6 c m^{2}$
The area of triangle is
$= \frac{1}{2} \times h e i g h t \times b a s e = \frac{1}{2} \times 3 \times 4 = 3 \times 2 = 6 c m^{2}$

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Similar questions

Q. Area of a triangle

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, with base

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and height

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Q. Question 1
Write True or False and justify your answer:

The area of a triangle with base 4cm and height 6cm is 24

c m^{2}

ABCD is a rectangle with O as any point in its interior. If $a r (△ A O D) = 3 c m^{2}$ and $a r (△ B O C) = 6 c m^{2},$ then area of rectangle ABCD is

The height of an equilateral triangle is 3 $\sqrt{3}$ cm. Its area is

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Q. In a parallelogram ABCD, AB = 6 cm and BC = 4 cm. The height corresponding to the base AB is 3 cm. Find the area of the parallelogram.

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The area of triangle with base 4 cm and height is 3 cm

The correct option is A 6 cm2The area of triangle is =12×height×base=12×3×4=3×2=6 cm2

The area of triangle with base $4 c m$ and height is $3 c m$

The correct option is A $6 c m^{2}$
The area of triangle is
$= \frac{1}{2} \times h e i g h t \times b a s e = \frac{1}{2} \times 3 \times 4 = 3 \times 2 = 6 c m^{2}$