Question

The area of triangle with sides $35$ cm, $66$ cm and $53$ cm is

• A. $924{\text{cm}}^2$
• B. $1336{\text{cm}}^2$
• C. $693{\text{cm}}^2$
• D. $1848{\text{cm}}^2$

Answer 1

The correct option is A $924{\text{cm}}^2$

Hen the sides of a triangle are given then the area is given by Heron's formula.

Area $=\sqrt{s(s-a)(s-b)(s-c)}$ where semiperimeter$\left(s\right)=\frac{a+b+c}{2}$

$\because s=\frac{35+66+53}{2}=77$
$⟹$ Area of $\Delta =\sqrt{77\times (77-35)\times (77-66)\times (77-53)}$
$=\sqrt{77\times 11\times 42\times 24}$
$=924{\text{cm}}^2$