Question

The area of two similar triangle respectively are 9 cm2 and 16 cm2 then find the ratio of the corresponding sides

Answer 1

Dear student,

$$\begin{gathered} Weknowthat, \\ \frac{ar\left(∆ABC\right)}{ar\left(∆DEF\right)}={\left(\frac{AB}{DE}\right)}^2--[where∆ABCand∆DEFaresimilartriangles] \\ \Rightarrow \frac{9}{16}={\left(\frac{AB}{DE}\right)}^2 \\ \Rightarrow \sqrt{\frac{9}{16}}=\frac{AB}{DE} \\ \Rightarrow \frac{AB}{DE}=\frac{3}{4} \\ Thustheratioofcorrespondingsidesare3:4 \end{gathered}$$

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