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Question

The area of two similar triangles are 169 cm2 and 121 cm2 respectively, If the longest side of the largest triangle is 26 cm, find the longest side of the smaller triangle?

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Solution

Given the area of Δ1=169cm2 and area of Δ2=121cm2
Let longest side of the smaller triangle be x.


For two similar triangles, the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

AreaofΔ1AreaofΔ2=(LongestsideofΔ1LongestsideofΔ2)2

Substituting the values, we get

169121=(26x)2


169121=26x

1311=26x

x=22cm

The longest side of smaller triangle is 22cm

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