The area of two similar triangles are $36 c m^{2}$ and $25 c m^{2}$ . If an altitude of the first triangle is $2.4 c m$ , find the corresponding altitude of the other triangle.

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Solution

given two triangles are similar

therefore ratio of their areas =square of ratios of corresponding altitudes

therefore $(\sqrt{\frac{25}{36}}) = \frac{2.4}{x}$

impies $x = 2.88$

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Similar questions

The areas of two similar triangles are $25 c m^{2}$ and $36 c m^{2}$ respectively. If the altitude of the first triangle is 2.4 cm, find the corresponding altitude of the other.

Q. The areas of two similar triangles are 25 cm² and 36 cm² respectively. If the altitude of the first triangle is 3.5 cm, then the corresponding altitude of the other triangle is
(a) 5.6 cm
(b) 6.3 cm
(c) 4.2 cm
(d) 7 cm

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The area of two similar triangles are 36 cm2 and 25 cm2. If an altitude of the first triangle is 2.4 cm, find the corresponding altitude of the other triangle.

given two triangles are similartherefore ratio of their areas =square of ratios of corresponding altitudestherefore (√2536)=2.4ximpies x=2.88

The area of two similar triangles are $36 c m^{2}$ and $25 c m^{2}$ . If an altitude of the first triangle is $2.4 c m$ , find the corresponding altitude of the other triangle.

given two triangles are similar

therefore ratio of their areas =square of ratios of corresponding altitudes

therefore $(\sqrt{\frac{25}{36}}) = \frac{2.4}{x}$

impies $x = 2.88$