Question

The area of two squares are in ratio $49:64$. Find the ratio of their circumferences.

Answer 1

$letradiusberandR\therefore \left(\frac{\pi r^2}{\pi R^2}\right)=\left(\frac{49}{64}\right)\therefore \left(\frac{r}{R}\right)=\left(\frac{7}{8}\right)nowratioofcircumferences=\left(\frac{2\pi r}{2\pi R}\right)=\left(\frac{r}{R}\right)=\left(\frac{7}{8}\right)$