Question

The area under acceleration-time graph represents

• A. displacement
• B. velocity
• C. change in velocity
• D. distance travelled

Answer 1

Answer: (C)

change in velocity

As we know $\frac{dv}{dt}$$=a$.

Then $dv=a.dt$

Integrating both side left from $v_{1}to{v}_2$ and right from $t_{1}to{t}_2$ so area under the curve between $t_{1}to{t}_2$ will give $v_2-v_1$.

I.e. change in velocity .