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Question

The area under acceleration-time graph represents


A
displacement
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B
velocity
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C
change in velocity
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D
distance travelled
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Solution

The correct option is D change in velocity
As we know $$\dfrac{dv}{dt}$$$$=a$$.
Then $$dv=a.dt$$
Integrating both side left from $$v_1 to\  v_2$$ and right from $$t_1\ to\  t_2$$ so area under the curve between $$t_1\  to\  t_2$$ will give $$v_2-v_1$$.
I.e. change in velocity .

Physics

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