Question

# The area under acceleration-time graph represents

A
displacement
B
velocity
C
change in velocity
D
distance travelled

Solution

## The correct option is D change in velocityAs we know $$\dfrac{dv}{dt}$$$$=a$$.Then $$dv=a.dt$$Integrating both side left from $$v_1 to\ v_2$$ and right from $$t_1\ to\ t_2$$ so area under the curve between $$t_1\ to\ t_2$$ will give $$v_2-v_1$$.I.e. change in velocity .Physics

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