The area under the curve 2{y} = [x] + 1,0≤y<1 (where {.} and [.] are the fractional part and greatest integer functions respectively) and the x axis is (in square units)
A
12
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B
1
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C
32
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Solution
The correct option is A12 2{y}=[x]+1 0≤y<1 {y=y}and0≤[x]+1<2−1≤[x]<1When−1<x<0y=00≤x<1y=12Area=12