The area under the curve drawn between the spectral emissive power E- wavelength - at a given temperature T for a black body is proportional to

3911

You visited us 3911 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Stefan-Boltzman's Law

The area unde...

Question

The area under the curve drawn between the spectral emissive power $E_{λ}$ , wavelength $λ$ at a given temperature $T$ for a black body is proportional to

T

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{T}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

T^{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

T^{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $T^{4}$
The power emitted by a black body is given by Stefan's law:
$P = σ A e T^{4}$
for a black body $e = 1;$
$P = σ A T^{4}$
And Energy spectral power $= P = E_{λ}$
Which is proportional to $T^{4}$

Suggest Corrections

Similar questions

Q. The spectral emissive power

E_{λ}

for a black body at temperature

T_{1}

is plotted against the wavelength and area under the curve is found to be

A

. At a different temperature

T_{2}

, the area is found to be

9 A

. Than

λ_{1} / λ_{2}

Q. The spectral emissive power

E_{λ}

for a black body at temperature

T_{1}

is plotted against the wavelength and area under the curve is found to be

A

. At a different temperature

T_{2}

, the area is found to be

9 A

. Than

λ_{1} / λ_{2}

Q. The spectral emissive power

E

for a body at temperature

T

is planted against the wavelength and area under the curve is found to be

A

. At a difference temperature

T_{2}

the area is found to be

9 A

. Then

λ_{1} / λ_{2} =

The spectral emissive power $E_{λ}$ for a body at temperature $T_{1}$ is plotted against the wavelength and area under the curve is found to be $A$ . At a different temperature $T_{2}$ the area`is found to be $9 A$ . Then $\frac{λ_{1}}{λ_{2}}$ is :

Q. The spectral emissive power

E_{λ}

for a body at temperature

T_{1}

is plotted against the wavelength and area under the curve is found to be

A

. At a different temperature

T_{2}

the area is found to be

9 A

. Then

\frac{λ_{1}}{λ_{2}} =

Join BYJU'S Learning Program

The area under the curve drawn between the spectral emissive power Eλ, wavelength λ at a given temperature T for a black body is proportional to

The correct option is B T4The power emitted by a black body is given by Stefan's law:P=σAeT4for a black body e=1;P=σAT4And Energy spectral power =P=EλWhich is proportional to T4

The area under the curve drawn between the spectral emissive power $E_{λ}$ , wavelength $λ$ at a given temperature $T$ for a black body is proportional to

The correct option is B $T^{4}$
The power emitted by a black body is given by Stefan's law:
$P = σ A e T^{4}$
for a black body $e = 1;$
$P = σ A T^{4}$
And Energy spectral power $= P = E_{λ}$
Which is proportional to $T^{4}$