Question

The area under the velocity-time graph of an object moving with uniform acceleration is expressed by the equation .

• A. $s=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2$
• B. $s=\mathrm{at}+\frac{1}{2}{\mathrm{at}}^2$
• C. $s=u+\frac{1}{4}{\mathrm{at}}^2$
• D. $u=\mathrm{at}+\frac{1}{2}{\mathrm{at}}^2$

Answer 1

The correct option is A $s=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2$

The equation $s=\mathrm{ut}+\frac{1}{2}{\mathrm{at}}^2$ relates the position (s) and time (t) of an object moving with constant acceleration (a) and the initial velocity (u).

The area under the velocity-time graph gives the displacement (s) of a moving object.