Question

The areas of squares drawn on the sides of a right-angled triangle of side length $13cm$, $12cm$ and $5cm$ will be equal to:(Follow the order sides to answer the areas of each squares )

• A. $144{cm}^2,169{cm}^2,125{cm}^2$
• B. $169{cm}^2,144{cm}^2,25{cm}^2$
• C. $125{cm}^2,144{cm}^2,169{cm}^2$
• D. $144{cm}^2,169{cm}^2,25{cm}^2$

Answer 1

Answer: (B)

$169{cm}^2,144{cm}^2,25{cm}^2$

Area of Square $=sid{e}^2$

$Sid{e}_H=$Hypotenuse of $△=13cm$

Area of Square drawn on Hypotenuse $=sid{e}^2={13}^2=169c{m}^2$

Say, $Sid{e}_B=$Base of $△=12cm$

Area of Square drawn on Base $=sid{e}^2={12}^2=144c{m}^2$

Say, $Sid{e}_A=$Altitude of $△=5cm$

Area of Square drawn on Altitude = $sid{e}^2=5^2=25c{m}^2$

$\therefore$ The areas of square on sides $13,12,5$ of a triangle are $169c{m}^2,144c{m}^2,25c{m}^2$. Option B.