The areas of two similar triangles ABC and DEF are $144 {c m}^{2}$ and $81 {c m}^{2}$ , respectively. If the longest side of larger triangle ABC is 36 cm, then the longest side of the smaller triangle DEF is

20 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

26 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

27 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

30 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 27 cm
Ratio of areas $= 144 : 81$
$∴$ ratio of sides $= 12 : 1$
Let the longest side be x. Then
$36 : x = 12 : 9 o r x = \frac{36 \times 9}{12} = 27 c m$
'

Suggest Corrections

Similar questions

The areas of two similar triangles $Δ A B C$ and $Δ D E F$ are $144 c m^{2}$ and $81 c m^{2}$ respectively. If the longest side of larger $Δ A B C$ be $36 c m$ , then the longest side of the smaller triangle $Δ D E F$ is
(a) $20 c m$
(b) $26 c m$
(c) $27 c m$
(d) $30 c m$