The areas of two similar triangles are 169 cm² and 121 cm² respectively. If the longest side of the larger triangle is 26 cm, what is the length of the longest side of the smaller triangle?

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Solution

Let ∆ABC and ΔPQR are similar triangles. The area of triangles is 169cm² and 121cm², respectively.

Longest side of the larger triangle is 26cm

TO FIND: length of longest side of the smaller side.

Suppose longest side of the larger triangle is BC and longest side of the smaller triangle is QR.

We know that the ratio of the areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.

Hence,

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Q. The areas of two similar triangles ABC and DEF are

144 {c m}^{2}

and

81 {c m}^{2}

, respectively. If the longest side of larger triangle ABC is 36 cm, then the longest side of the smaller triangle DEF is

Q. The area of two similar triangles

Δ A B C

and

Δ D E F

are 144

c m^{2}

and 81

c m^{2}

respectively If the longest side of larger

Δ A B C

be 36 cm then the longest side of the smaller triangle

Δ D E F

The areas of two similar triangles $Δ A B C$ and $Δ D E F$ are $144 c m^{2}$ and $81 c m^{2}$ respectively. If the longest side of larger $Δ A B C$ be $36 c m$ , then the longest side of the smaller triangle $Δ D E F$ is
(a) $20 c m$
(b) $26 c m$
(c) $27 c m$
(d) $30 c m$

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The areas of two similar triangles are 169 cm2 and 121 cm2 respectively. If the longest side of the larger triangle is 26 cm, what is the length of the longest side of the smaller triangle?

The areas of two similar triangles are 169 cm² and 121 cm² respectively. If the longest side of the larger triangle is 26 cm, what is the length of the longest side of the smaller triangle?