Question

The areas of two similar triangles are 49 $c{m}^2$ and 64 $c{m}^2$ respectively. The ratio of their corresponding sides is

• A. 49:64
• B. 7:8
• C. 16:49
• D. None of these

Answer 1

The correct option is B

7:8

We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

$\frac{(sideoffirst△{)}^2}{(corr.sideof2nd△{)}^2}$ = $\frac{49}{64}$

$\Rightarrow$ Ratio of corr. sides = 7:8.