Question

The areas of two similar triangles are $81c{m}^2$ and $49c{m}^2$ respectively. Find the ratio i4their corresponding heights. What is the ratio of their corresponding medians?

Answer 1

ratio of area of two similar triangles = (ratio of the corresponding sides of similar triangles)

$\frac{81}{49}$= (ratio of corresponding heights)
Ratio of corresponding heights =$\sqrt{\frac{81}{49}}$= $\frac{9}{7}$
Ratio of corresponding medians = Ratio of corresponding heights =$\frac{9}{7}$