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Question

The argument of the complex number 1+i1i where i=1, is

A
π
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B
π2
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C
π2
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D
π
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Solution

The correct option is C π2
Z==1+i1i
Z=1+i1i×1+i1+i
Z=(1+i)212i2=1+2i+i22
Z=i
Z=eiπ/2reiθ
θ=π2
Hence argument is
θ=π2

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