Question

The argument of the complex number $\frac{2+3i}{(3+i){(1+2i)}^2}$ is equal to

• A.
• B.
• C.

Answer 1

The correct option is A

We have z = $\frac{2+3i}{(3+i)+{(1+2i)}^2}=\frac{2+3i}{3+i+1-4+4i}$
Hence, we have arg (z) = ${tan}^{-1}\left(\frac{-2}{3}\right)$