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Question

The arithmetic mean of a set of 20 values is 55. What will be the new mean, if each of the 20 value is: [4 MARKS]
i) increased by 5?
ii) decreased by 5?
iii) multiplied by 5?
iv) divided by 5?

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Solution

Each Part: 1 Mark

Let the 20 values be x1,x2,,x20
Sum of these 20 values =x1+x2++x20
Given mean of the 20 values = 55
x1+x2++x2020=55
x1+x2++x20=55×20=1100
i) Each of the 20 values is increased by 5
New values will be (x1+5),(x2+5),(x20+5)
Their sum
=(x1+5)+(x2+5)++(x20+5)
=(x1+x2++x20)+20×5
=1100+100=1200
Total number of values = 20
The mean of new values =120020=60

ii) Each of the 20 values is decreased by 5
New values will be (x15),(x25),(x205)
Their sum = 1100 - 100 = 1000
Total number of values = 20
The mean of new values =100020=50

iii) Each of the 20 values is multiplied by 5
New values will be 5x1,5x2,5x20
Their sum =5×1100=5500
Total number of values = 20
The mean of new values =550020
=275

iv) Each of the 20 values is divided by 5
New values will be x15,x25,,x205
Their sum =15×1100=220
Total number of values = 20
The mean of new values =22020=11

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