The arithmetic mean of ${^{n} C}_{0}, {^{n} C}_{1}, . . . . {^{n} C}_{n}$ , is

\frac{1}{n}

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\frac{2^{n}}{n}

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\frac{2^{n - 1}}{n}

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\frac{2^{n + 1}}{n}

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Solution

The correct option is D $\frac{2^{n}}{n}$
Clearly,
Required mean $= \frac{{^{n} C}_{0} + {^{n} C}_{1} + . . . + {^{n} C}_{n}}{n} = \frac{2^{n}}{n}$

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