The arithmetic mean of n numbers is $¯ x$ the sum of first (n - 1) number is k. The nth number is

n ¯ x - k

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n ¯ x - - 2 k

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n ¯ x + k

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n ¯ x + 2 k

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Solution

The correct option is A $n ¯ x - k$
Sum of all number = $n ¯ x$
Sum of first $(n - 1)$ numbers $=$
nth number $= n ¯ x - k$

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