The arithmetic mean of the first $n$ natural number is

\frac{(n + 1)}{2}

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\frac{(n - 1)}{2}

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\frac{n}{2}

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None of these

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Solution

The correct option is A $\frac{(n + 1)}{2}$
The arithmetic mean of first n natural number i.e. $1, 2, 3, . . . ., n$
$= \frac{1 + 2 + 3 + . . . + n}{n} = \frac{n (n + 1)}{2 n} = \frac{n + 1}{2}$

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