The arithmetic mean X of six numbers 2, 3, 4, 1, 5, 7 is equal to their sum divided by the number of quantities. Frame a formula.

X =

\frac{2 + 3 + 4 + 1 + 5 + 7}{8}

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X =

\frac{2 + 3 + 4 + 1 + 5 + 7}{3}

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X =

\frac{2 + 3 + 4 + 1 + 5 + 7}{6}

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X =

\frac{3 + 4 + 1 + 5 + 7}{6}

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Solution

The correct option is C X = $\frac{2 + 3 + 4 + 1 + 5 + 7}{6}$
Given that arithmetic mean X of six numbers, 2, 3, 4, 1, 5, 7 is equal to their sum divided by the number of quantities, the formula is

$X = \frac{2 + 3 + 4 + 1 + 5 + 7}{6}$

So, option C is correct.

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Similar questions

:

X	$2 - 3$	$3 - 4$	$4 - 5$	$5 - 6$	$6 - 7$	$7 - 8$
F	$1$	$2$	$2$	$2$	$3$	$1$

1, 2^{1 / 2}, 3^{1 / 3}, 4^{1 / 4}, 5^{1 / 5}, 6^{1 / 6}, 7^{1 / 7}, i s 3^{1 / 3} .

x^{1 / x}

0 < x < e

\frac{a}{3} = 7

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