The arrangement of following compounds:
$i$ . Bromomethane
$i i$ . Bromoform
$i i i$ . Chloromethane
$i v$ . Dibromomethane
In the increasing order of their boiling point is :

i i i < i < i v < i i

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

i v < i i i < i < i i

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i i < i i i < i < i v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

i < i i < i i i < i v

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $i i i < i < i v < i i$
As the molecular mass increases boiling point increases due to increased polar character. Hence,
$i i i < i < i v < i i$

Suggest Corrections

Similar questions

The arrangement of the following compounds:

i. Bromomethane

ii. Bromoform

iii. Chloromethane

iv. Dibromomethane

C H_{3} C H_{2} C H_{2} B r

C H_{3} C H_{2} C H_{2} C H_{2} B r

(C H_{3})_{2} C H C H_{2} B r

(C H_{3})_{3} C B r

I . C_{9} H_{20} I I . C_{8} H_{18}

I I I . (C H_{3})_{2} C - (C H_{2})_{4} - C H_{3}

I V . C H_{3} - C H_{3} | C | C H_{3} - C H_{3} | C | C H_{3} - C H_{3}

I . B a C l_{2}

II . S r C l_{2}

III . C a C l_{2}

IV . M g C l_{2}

V . B e C l_{2}

Join BYJU'S Learning Program