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Question

The arrangement of following functions in descending order of their periods:
A) 3cosx2+sinx2
B) 3tanx3cotx3
C) 3sin3x+4cos3x
D) sin2x2cos2x

A
C,A,B,D
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B
D,C,A,B
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C
A,B,C,D
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D
B,D,C,A
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Solution

The correct option is D A,B,C,D
(A) Period of cosx2 is 2π12=4π
Period ofsinx2 is 2π12=4π
Period of A is 4π

(B) Period of tanx3 is π13=3π
Period of cotx3 is π13=3π
Hence, period B is 3π

(C) period of sin3x is 2π as period of (sinx)2m is π and (sinx)2m+1 is 2π
Period of cos3x is 2π as period of (cosx)2m is π and (cosx)2m+1 is 2π
period of C is 2π

(D) Period of sin2x is π
Period of cos2x is π
period of D is π
Hence, sequired ordes is ABCD.

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