CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
166
You visited us 166 times! Enjoying our articles? Unlock Full Access!
Question

The arrangement of following functions in descending order of their periods:
A) 3cosx2+sinx2
B) 3tanx3cotx3
C) 3sin3x+4cos3x
D) sin2x2cos2x

A
C,A,B,D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
D,C,A,B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A,B,C,D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
B,D,C,A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D A,B,C,D
(A) Period of cosx2 is 2π12=4π
Period ofsinx2 is 2π12=4π
Period of A is 4π

(B) Period of tanx3 is π13=3π
Period of cotx3 is π13=3π
Hence, period B is 3π

(C) period of sin3x is 2π as period of (sinx)2m is π and (sinx)2m+1 is 2π
Period of cos3x is 2π as period of (cosx)2m is π and (cosx)2m+1 is 2π
period of C is 2π

(D) Period of sin2x is π
Period of cos2x is π
period of D is π
Hence, sequired ordes is ABCD.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon