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Question

The arrangement of (CH3)3C−,(CH3)2CH−,CH3CH2− when attached to benzene or unsaturated group in increasing order of activating effect is:

A
(CH3)3C<(CH3)2CH<CH3CH2
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B
CH3CH2<(CH3)2CH<(CH3)3C
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C
(CH3)2CH<(CH3)3C<CH3CH2
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D
(CH3)3C<CH3CH2<(CH3)2CH
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Solution

The correct option is A (CH3)3C<(CH3)2CH<CH3CH2
The order of increasing activation order is
(CH3)3C<(CH3)2CH<CH3CH2
The greater the number of alkyl groups attached to a positive carbon atom, hyper conjugation increases and thus stability the cation.
As (CH3)3C has more alkyl groups attached it is more stable.

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