Question

The arrangement of particles of a known substance at the same pressure at two different temperatures is shown in the diagrams.




The melting point and boiling point of the substance is:

• A. $-{132}^{o}C,-{163}^{o}C$
• B. $-{189}^{o}C,-{98}^{o}C$
• C. $-{166}^{o}C,-{103}^{o}C$
• D. $-{115}^{o}C,-{86}^{o}C$

Answer 1

The correct option is C $-{166}^{o}C,-{103}^{o}C$

In the first diagram, the particles of the compound are in liquid state at $-{140}^{o}C$ that means it must has the melting point > $-{140}^{o}C$.

In the second diagram, it shows that the particles are in gaseous state at $-{100}^{o}C$ .It means that the boiling point of the compound is > $-{100}^{o}C$.

So, option c is the correct answer in which the melting point is greater than $-{140}^{o}C$ and the boiling point is greater than \(-100o^C).