The arrangement of the following compounds:

i. Bromomethane

ii. Bromoform

iii. Chloromethane

iv. Dibromomethane

iii < i < iv < ii

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iv > iii > i > ii

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ii > iii > i > iv

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i> ii > iii > iv

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Solution

The correct option is A
iii < i < iv < ii

$C H_{3} - C I < C H_{3} - B r < C H_{2} B r_{2} < C H B r_{3}$

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