The arrangement of the following conics in the ascending order of their eccentricities is A) r(4+cosθ)=8 B) 1r=35−3cosθ5 C) 8=r(1+3cosθ)
A
B,C,A
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B
B,A,C
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C
A,B,C
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D
A,C,B
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Solution
The correct option is CA,B,C General equation of conic in polar form is lr=1±ecosθ A) r(4+cosθ)=8⇒2r=1+14cosθ⇒e=14 B) 1r=35−3cosθ5⇒5/3r=1−cosθ⇒e=1 C) 8=r(1+3cosθ)⇒8r=1+3cosθ⇒e=3