The arrangement of the following conics in the descending order of their lengths of semi latus rectum is A) 6=r(1+3cosθ) B) 10=r(1+3cosθ) C) 8=r(1+3cosθ) D) 12=r(1+3cosθ)
A
D,A,B,C
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B
B,C,D,A
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C
D,B,C,A
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D
A,C,B,D
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Solution
The correct option is DD,B,C,A Comparing given equation with standard equation r(1+ecosθ)=l where l is semi latus rectum Hence order is D,B,C,A