Question

The arrangement of the following quadratic equations in the descending order of their sum of the roots.
A: $x^2+11=0$
B: $(x+2)(x-3)=0$
C: $5x^2+4x=0$
D: $2x^2+3x-5=0$

• A. $A,B,C,D$
• B. $D,C,B,A$
• C. $B,A,C,D$
• D. $A,C,B,D$

Answer 1

Answer: (C)

$B,A,C,D$

$\alpha +\beta =\frac{-b}{a}$
$\alpha \beta =\frac{c}{a}$
For equation $a{x}^2+bx+c=0$
(A) $x^2+11=0$
$\alpha +\beta =0$
(B) $(x+2)(x-3)=0$
$x=-2,x=3$
$x_1+x_2=1$
(C) $5x^2+4x=0$
$x_1+x_2=\frac{-4}{5}$
(D) $2x^2+3x-5=0$
$\alpha +\beta =\frac{-3}{2}$