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Coordination and Oxidation Number

The arrangeme...

Question

The arrangement of $X^{-}$ ions around $A^{+}$ ion in soild $A X$ is given in the figure(not drawn to scale). If the radius of $X^{-}$ is 250 pm, the radius of $A^{+}$ is:

104

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125

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183

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Solution

The correct option is A $104$ pm
$1) (a)$ The figure represents an octahedral void
$\frac{r A^{+}}{r X^{-}} = 0.414$
$r A^{+} = 0.414 \times 250 = 104 pm$

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The arrangement of X− ions around A+ ion in soild AX is given in the figure(not drawn to scale). If the radius of X− is 250 pm, the radius of A+is:

The correct option is A 104 pm1)(a) The figure represents an octahedral void rA+rX−=0.414 rA+=0.414×250=104 pm

The arrangement of $X^{-}$ ions around $A^{+}$ ion in soild $A X$ is given in the figure(not drawn to scale). If the radius of $X^{-}$ is 250 pm, the radius of $A^{+}$ is:

The correct option is A $104$ pm
$1) (a)$ The figure represents an octahedral void
$\frac{r A^{+}}{r X^{-}} = 0.414$
$r A^{+} = 0.414 \times 250 = 104 pm$