The arrangment of the slopes of the normals to the curve y=elog(cosx) in the ascending order at the points given below. A)x=π6,B)x=7π4,C)x=11π6,D)x=π3
A
C,B,D,A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
B,C,A,D
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
A,D,C,B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
D,A,C,B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is CC,B,D,A We have, y=elogcosx=(cosx)loge[∵alogbc=clogba]=cosx ⇒dydx=−sinx=m(say) Thus slope of normal to the given curve at any point is, m′=−1m=1sinx Now, m′π6=2,m′7π4=−√2,m′π6=−2,m′π6=√32 Clearly ascending order is, C,B,D,A Note: Given function is not defined where cosx<0