Question

The ascending arrangement of $\frac{2}{3}$, $\frac{6}{7}$, $\frac{13}{21}$, is-

• A. $\frac{6}{7}$, $\frac{2}{3}$, $\frac{13}{21}$
• B. $\frac{13}{21}$, $\frac{2}{3}$, $\frac{6}{7}$
• C. $\frac{6}{7}$, $\frac{13}{21}$, $\frac{2}{3}$
• D. $\frac{2}{3}$, $\frac{6}{7}$, $\frac{13}{21}$

Answer 1

The correct option is B

$\frac{13}{21}$, $\frac{2}{3}$, $\frac{6}{7}$

Take the LCM of the denominators which is 21.

$\frac{2}{3}$ =$\frac{14}{21}$

$\frac{6}{7}$ = $\frac{18}{21}$

$\frac{13}{21}$ = $\frac{13}{21}$

So the ascending order of the given numbers is

$\frac{13}{21}$ < $\frac{14}{21}$ < $\frac{18}{21}$

$\frac{13}{21}$ < $\frac{2}{3}$ < $\frac{6}{7}$