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Question

The asymptotes of the hyperbola xy−3x+4y+2=0

A
x=4
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B
x=4
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C
y=3
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D
y=3
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Solution

The correct options are
A x=4
D y=3
Since the equation of a hyperbola and its asymptotes differ in constant terms only. Therefore, the equations of asymptotes of the given hyperbola are given by xy3x+4y+k=0
where k is a constant to be determined by the condition that abc+2fghaf2bg2ch2=0
i.e., 0+2×2×(32)×1200k×(12)2=0k=12
Asymptotes of the given hyperbola are xy3x+4y12=0 or (x+4)(y3)=0
i.e., x=4 and y=3.

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