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B
x=4
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C
y=−3
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D
y=3
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Solution
The correct options are Ax=−4 Dy=3 Since the equation of a hyperbola and its asymptotes differ in constant terms only. Therefore, the equations of asymptotes of the given hyperbola are given by xy−3x+4y+k=0
where k is a constant to be determined by the condition that abc+2fgh−af2−bg2−ch2=0
i.e., 0+2×2×(−32)×12−0−0−k×(12)2=0⇒k=−12
∵ Asymptotes of the given hyperbola are xy−3x+4y−12=0 or (x+4)(y−3)=0