The asymptotes of the hyperbola xy=hx+ky are
x−k=0 and y−h=0
x+h=0 and y+k=0
x−k=0 and y+h=0
x+h=0 and y−h=0
Given : The hyperbola xy=hx+ky
⇒x(y−h)=k(y−h)+kh
⇒(x−k)(y−h)=kh
∴ Joint equation of asymptotes is (x−k)(y−h)=0
Hence, the equation of asymptotes are x−k=0 and y−h=0
The area of the triangle formed by the lines, y = x, x + y = 2 and the line through p(h, k) and parallel to the x-axis is 4h2, then the point P lies on