Question

The atomic mass of ${}_7{N}^{15}$ is $15.000108amu$ and that of ${}_8{O}^{16}$ is $15.994915amu$. The minimum energy required to remove the least tightly bound proton is (mass of proton is $1.007825amu)$

• A. $0.013018amu$
• B. $12.13MeV$
• C. $13.018MeV$
• D. $12.13eV$

Answer 1

The correct option is B $12.13MeV$

${}_8^{16}O{\to }_7^{15}N{+}_1^{1}P$

$\Delta m=[15.000108+1.007825-15.994915]$
$=0.013018amu$

$\Delta E=0.013018\times 931.478$ MeV
$=12.13MeV$