The atomic mass of an element is $197$ and its atomic number is $79$ . Find the number of protons, neutrons, and electrons.

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Solution

The element with atomic mass $197$ and atomic number $79$ is Gold ${}_{79}^{197}{Au}$ .
Number of protons = $Z = Atomic Number$
$Z = 79$
Number of neutrons can be calculated as = Atomic Mass - Atomic Number
=197-79
= 118 neutrons
Hence, the element Gold ( $Au$ ) has $79 p r o t o n s a n d 118 n e u t r o n s$ .

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The atomic mass of an element is 197and its atomic number is 79. Find the number of protons, neutrons, and electrons.

The element with atomic mass 197and atomic number 79 is Gold Au79197.Number of protons = Z=AtomicNumber Z=79Number of neutrons can be calculated as = Atomic Mass - Atomic Number =197-79 = 118 neutronsHence, the element Gold (Au) has 79protonsand118neutrons.

The atomic mass of an element is $197$ and its atomic number is $79$ . Find the number of protons, neutrons, and electrons.