The atomic mass of Uranium 23892U is 238-0508 u- while that of Thorium 23490Th is 234-0436 u- and that of Helium 42He is 4-0026 u- Alpha decay converts 23892U into 23490Th as shown below- 23892U - 23490Th - 42He - energyDetermine the energy released in this reaction-

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Binding Energy

The atomic ma...

Question

The atomic mass of Uranium $_{92}^{238} U$ is 238-0508 u, while that of Thorium $_{90}^{234} T h$ is 234.0436 u, and that of Helium $_{2}^{4} H e$ is 4.0026 u. Alpha decay converts $_{92}^{238} U$ into $_{90}^{234} T h$ as shown below:
$_{92}^{238} U \to_{90}^{234} T h +_{2}^{4} H e + e n e r g y$
Determine the energy released in this reaction.

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_{92} U^{238}

238.0508 u

_{90} {Th}^{234}

234.0436 u

_{2} {He}^{4}

4.0026 u

α - decay

_{92} U^{238}

_{90} {Th}^{234}

[1 u \times c^{2} = 931.5 MeV]

_{90}^{234} T h

_{90}^{234} T h \to_{z}^{A} X +_{2}^{4} H e .

_{92}^{238} U

_{90}^{234} T h,

_{91}^{234} P a,

_{92}^{234} U,

_{90}^{230}

T h

_{88}^{226} R a

The radioactive decay of uranium into thorium is represented by the equation
$_{92}^{238} U \to_{90}^{234} T h + x$
What is x?

- 226

2.8 \times 10^{6}

- 238

_{92}^{238} U

_{88}^{226} R a

_{88}^{226} R a

_{92}^{238} U

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