wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The atomic masses of the hydrogen isotopes are
m1H1=1.007825 amu
m1H2=2.014102 amu
m1H3=3.016049 amu
The energy released in the reaction
1H2+1H21H3+1H1
is nearly:

A
1 MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4 MeV
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
8 MeV
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 4 MeV
Mass defect: ΔM=2m1H2(m1H1+m1H3)
ΔM=2(2.014202)(1.007825+3.016049)=4.33×103 amu
Energy released, E=ΔM×931 MeV
E=4.33×103×9314MeV

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mass - Energy Equivalence
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon