The atomic number of an element is 20. In the modern periodic table, this element is placed in :

(a) 2nd period (b) 4th period (c) 3rd period (d) 1st period

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Solution

(b) 4^th period.

Electronic configuration: K = 2 L = 8 M = 8 N = 2

Hence, from the electronic configuration, it is clear that the outermost electron goes into the 4^th shell. So, the element would be placed in the 4^th period.

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