The atomic number of an element X is 12.
(a) What must an atom of X do to attain the nearest inert gas electron configuration?
(b) Which inert gas is nearest to X?

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Solution

(a) An atom of X must lose its two electrons to attain the nearest inert gas electron configuration.

(b) After losing two electrons, it will have 10 electrons with electronic configuration 2,8, which represents neon gas. So, neon gas is the nearest inert gas to X.

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The atomic number of an element X is 12. (a) What must an atom of X do to attain the nearest inert gas electron configuration? (b) Which inert gas is nearest to X?

(a) An atom of X must lose its two electrons to attain the nearest inert gas electron configuration. (b) After losing two electrons, it will have 10 electrons with electronic configuration 2,8, which represents neon gas. So, neon gas is the nearest inert gas to X.

The atomic number of an element X is 12.
(a) What must an atom of X do to attain the nearest inert gas electron configuration?
(b) Which inert gas is nearest to X?

(a) An atom of X must lose its two electrons to attain the nearest inert gas electron configuration.

(b) After losing two electrons, it will have 10 electrons with electronic configuration 2,8, which represents neon gas. So, neon gas is the nearest inert gas to X.