The atomic number of cobalt is $27$ . The EAN of cobalt in $N a_{3} [C o (N O_{2})_{4} C l_{2}]$ is :

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Solution

The correct option is D 36
The atomic number of cobalt is 27. The EAN of cobalt in $N a_{3} [C o (N O_{2})_{4} C l_{2}]$ is 36.
$E A N = Z - X + Y$

$Z$ is the atomic number of $C o$ (27).
$X$ is the oxidation state of Co=3
$Y$ is double of its coordination number= 12

$E A N = X - Y + Z = 27 - 3 + 12 = 36$

Hence, option $C$ is correct.

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