The atomic number of Cu is $29$ . The $E A N$ (Effective Atomic Number) of $C u$ in ${[C u {(N H_{3})}_{4}]}_{4}^{2 +}$ is:

35

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36

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49

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40

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Solution

The correct option is A $35$
The $E A N$ is calculated as the sum of electrons on metal ion and electrons donated by ligands.
Here, $C u^{+ 2}$ has 27 electrons and four $N H_{3}$ give $= 4 \times 2 = 8$ electrons. So, $E A N$ $= 27 + 8 = 35$ .

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Similar questions

The effective atomic number of central Cu (At. No. 29) metal in $[C u (N H_{3})_{4}] S O_{4}$ is

[C u (N H_{3})_{4}]^{2 +}

C u^{+}

(a t o m i c n u m b e r = 29)

P t = 78, F e = 26, Z n = 30, C u = 29

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