The atomic number of elements A, B and C are (Z - 1), Z and (Z + 1) respectively. B is an inert gas (not helium). Which element has the lowest ionization energy? Why?
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Solution
Ionisation energy is the amount of energy required to remove the valence electron from an atom.
As C is an alkali metal with atomic number Z+ 1 and has one electron in the valence shell. Therefore, it will readily loose the valence electron to achieve stable noble gas configuration.