The atomic number of elements X, Y and Z are (A -2), A and (A + 2), respectively. Y is a noble gas (not helium) then predict the group to which X, Y, and Z belong and also predict the formula of a molecule formed by X and Z?

Open in App

Solution

According to the question, Y can be any noble gas (excluding helium), meaning it belongs to group 18 or zero.
X = A-2, therefore $18 - 2 = 16$ . X belongs to the 16th group, sometimes known as $V I A$ .
Z = A+2, therefore $18 + 2 = 20$ . Z is a member of the second group or $I I A$ .
The electronic configuration of X (16) is $= 2, 8, 6$ , indicating that its valency is $- 2$ .
Z (20) has an electronic structure of $2, 8, 8, 2$ indicating that its valency is $+ 2$ . The compound formed via cross-multiplication of valency has the formula $X Z$ .

Suggest Corrections

Similar questions

(a) Elements X, Y and Z have atomic numbers 6, 9 and 12 respectively. Which one :

(i) forms an anion, (ii) forms a cation,

(b) State the type of bond between Y and Z and give its molecular formula.

Q. Element X combines with element Y to form a compound Z. If the atomic numbers of X and Y are 12 and 16 respectively, the formula of Z is :-

Answer the following questions:-

(a)the atomic number of an element X is 3identify the group and the period in which elemens X is present.

(b) three elements X,Y,Z have consecutive atomic numbers if element X is a noble gas what will be the symbol for the ion of element Z in its compound?

(c)what will be the formula of the compound formed between the element X and Z

A, B, C

are three elements with the atomic number

Z - 1, Z, Z + 1

respectively.

B

is an inert gas. Predict the group of

A

and

C

If three elements X, Y and Z form a triad and atomic weights of X and Z are 9 and 40, respectively, then the atomic weight of an element Y is _____.

Join BYJU'S Learning Program